(3x^3+4x-1)(x^2+1)=

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Solution for (3x^3+4x-1)(x^2+1)= equation: 


Simplifying
(3x3 + 4x + -1)(x2 + 1) = 0

Reorder the terms:
(-1 + 4x + 3x3)(x2 + 1) = 0

Reorder the terms:
(-1 + 4x + 3x3)(1 + x2) = 0

Multiply (-1 + 4x + 3x3) * (1 + x2)
(-1(1 + x2) + 4x * (1 + x2) + 3x3 * (1 + x2)) = 0
((1 * -1 + x2 * -1) + 4x * (1 + x2) + 3x3 * (1 + x2)) = 0
((-1 + -1x2) + 4x * (1 + x2) + 3x3 * (1 + x2)) = 0
(-1 + -1x2 + (1 * 4x + x2 * 4x) + 3x3 * (1 + x2)) = 0
(-1 + -1x2 + (4x + 4x3) + 3x3 * (1 + x2)) = 0
(-1 + -1x2 + 4x + 4x3 + (1 * 3x3 + x2 * 3x3)) = 0
(-1 + -1x2 + 4x + 4x3 + (3x3 + 3x5)) = 0

Reorder the terms:
(-1 + 4x + -1x2 + 4x3 + 3x3 + 3x5) = 0

Combine like terms: 4x3 + 3x3 = 7x3
(-1 + 4x + -1x2 + 7x3 + 3x5) = 0

Solving
-1 + 4x + -1x2 + 7x3 + 3x5 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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